The objective of this experiment is to use the Archimedes principle to evaluate the specific weight of all of the separate materials. This objective of this experiment is significant in that it gives valuable information on how to determine the material composition of an object when given very vague information. From information learned in the accompanying Fluid Mechanics lecture course, basic formulas can be applied to solve for the specific weight of the object in question. The experiment performed will involve the buoyancy principle and include calculating the volume displaced of a submerged object. This is laboratory experiment under a controlled environment. The results of this experiment can be found by using the weight of each object when dry as well as submerged in water in order to determine the specific weights of the objects. This concludes the Archimedes principle to be true in that the collected values were very close to those of the available accepted data for the respected materials. These findings will likewise set the basis for fluid mechanics study to come during the remainder of this course.
Objective & Introduction:
The objective of this lab experiment is to gather enough information to be
able to use the buoyancy principle to determine specific weight of multiple objects. Submarines apply Archimedes Principle when changing depth. A submarine dives deeper by opening its ballast tank, collecting enough water to increase the submarines weight to an amount greater than the buoyant force. By pushing water out of the ballast tanks, the submarine becomes lighter than the buoyant force, allowing the submarine to rise. Archimedes Principle is used in everyday industries which involve buoyancy, to include watercraft, weather balloons, and even life-preservers. It is necessary to know whether or not something will float, as intended, or sink below the surface of the fluid in which it is In the year 250 B.C. Greek mathematician Archimedes of Syracuse published On Floating Bodies, a book containing various scientific and mathematical principles which he had scrutinized and eventually proved through rigorous trial and error . While never fully verified, the legend of the buoyancy principle was verified by Archimedes himself after noticing the water level rise after stepping into his bathtub one night. His exclamation of Eureka!, Greek for I found it marked this significance and had been used as a verbal mark for discovery in the English language ever since. In modern engineering, Archimedes principle can be seen in nearly every real world application. In the basic sense, calculations for ocean-going vessels are wholly dependent on the buoyancy principle. For a more broad sense, the principle of material composition verification can nearly always come back to soaking and floating an object. And for a more abstract outlook, the floating of blimps, balloons, and lighter-than-air craft is dependent on the fact that their specific weight is equal to their weight displaced divided by their displaced volume.
Theory & Experimental Methods:
Archimedes Principle states that objects in a specific medium (i.e. air or water) experience an upward force known as buoyant force. In order for something to stay afloat, this force must be equal in magnitude or in the case of lift with a hot-air balloon, greater than, the weight of the volume displaced by that object. Moreover, this amount of substance or in the case of this experiment; the water (or fluid) displaced will be equal to the volume of water displaced divided by the specific weight of the object. Figure 1 illustrates the relationship between weight force and buoyant
force. By performing this experiment, one can evaluate the specific weight of the material by using the submerged weight and the dry weight difference.
Figure 1. Buoyant Force VS. Weight Force
The student will measure the dry weight of each of the materials provided and then will measure the wet weight of those materials and container. If applicable, the student will also use the submerged height of the object if it is submerged. Wfluid Displaced =Î³fluid * VD Eqn. (1) FB = WB WS Eqn. (2)
FB = VD *Î³ fluidEqn. (3)
VD = F _B /Î³_fluid Eqn. (4)
Where: FB : Buoyant Force (lb)
VD : Volume of fluid displaced (ft3)
WFluid Displaced: Weight of fluid displaced Dry Weight [lb]
WD : Dry Weight [lb]
Ws : Submerged Weight (lb)Î³ : Specific Weight [lb / ft3]
Î³fluid: Specific Weight [lb/ft3]
Assume that the specific weight of air is negligible and that pressure is at normal atmospheric.
Determine the dry weight of each of the given objects: wood, aluminum, quartz, aluminum cylinder, and streel ball
Measure the submerged weight of each object using the scale
Measure the submerged depth if the object is floating
Find the submerged volume of each object using áµ§water = 62.4 lb/ft3
For completely submerged objects this is equal to the total volume of the object
For floating objects this is just the volume below the liquid surface.
Find the total volume of each object
Calculate the specific weight of each material
Figure 1. Wood Block Sample A
Figure 1. Aluminum Sample B
Figure 3. Aluminum Cylinder Sample
Figure 2. Steel Sample B
¢ Container: used for holding the water which will act as the fluid medium for measurement. ¢Scale, no preference